Question

find the value of k so that the zeros of the quadratic polynomial 3x2 - kx +14 are in the ratio 7 : 6 ​

Answer 1

Step-by-step explanation:

Let the zeros be 7a, 6a

So 7a × 6a = 14/3

42a^2 = 14/3

a^2 = 1/9

a = 1/3

Also sum of zeroes = k/3

7a + 6a = k/3

13a = k/3

13×1/3 = k/3

So, k = 13

Hope it helps u

Answer 2

Answer:

The value of k=13 for the given problem