Question

find the value of k so that x-1 is a factor of polynomial 5 x^2 + 4 x^2 - 6 X + 2 k​

Answer 1

Here is the answer...!!

Refer to the attachment..!!!

Answer 2

Step-by-step explanation:

Given:

5 x² + 4 x² - 6 X + 2 k

x - 1 Is a factor.

so,

x=1 is its one root.

=> 9x² - 6x + 2k = 0

Put x=1

=> 9(1)² - 6(1) + 2k = 0

=> 9 - 6 + 2k = 0

=> +3 + 2k = 0

$2k = - 3 \\ \\ k = - \frac{3}{2}$

Ans: value of k is - 3/2

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How many roots does quadratic equation have?

★Standard form is ax² + bx + c , where a,b,c are respective coefficients.

★ Any quadratic equation has only 2 roots.

★The roots may be real numbers or imaginary numers.

★if its imaginary roots then it will always be in pairs.