Question

Find the value of K so that x^3-3x^2+4x+k is exactly divisible by x-2​

Answer 1

Answer:

12

Step-by-step explanation:

Since x-2 exactly divides p(x)

therefore x-2=0

x=2 is the zero of p(x)

Now substituting the x with 2

p(x)=x^3-3x^2+4x+k=0

=(2)^3-3*(2)^2+4*2+k=0

=8-12+8+k=0

=k=12

Answer 2

Answer:

Step-by-step explanati

on: