Question

find the value of K so that X,X+2,X+6 are three consecutive terms of Gp.​

Answer 1

$\huge {\underline {\underline {\mathbb {\blue{Answer:-}}}}}$

In geometric progression

$\frac {2nd\:term}{1st\:term}=\frac {3rd\:term}{2nd \:term}$

so,

$\frac {x+2}{x}=\frac {x+6}{x+2}$

$(x+2)^2=x(x+6)$

$x^2+4x+4=x^2+6x$

$4x+4=6x$

$2x=4$

$x=2$

Answer 2

Answer:

$\huge\purple {\mathfrak{Hello!!! }}$

Step-by-step explanation:

as we know...in the geometrical expression :

$a2 \div a1 = a3 \div a2$

$(x + 2) \div x = (x + 6) \div (x + 2) \\ \\ {x + 2}^{2} = x(x + 6) \\ \\ {x}^{2} + 4 + 4x = {x}^{2} + 6x \\ \\ 4 = 2x \\ \\ x = 2$

hope it helps uh....

btw telugu?

$\huge\purple {\mathfrak{thank uh!!! }}$