Question

Find the value of k solution has many infinitely solution 2x+3y-5=0 , 6x+ky-15=0

Answer 1

condition of infinite many solution is a1/a2 =b1/b2=c1/c2
here a1= 2       ,     a2= 6
        b1= 3       ,     b2= k
        c1= -5      ,     c2= -15

then it forms 2/6=3/k=-5/-15
                     1/3=3/k=1/3
            
                     1/3=3/k (no do cross multiplication)
                      k= 3x3
                      k=9 {ANSwer}

 

Answer 2

answer is here....

2x+3y-5=0
a1+b1+c1=0

6x+ky-15=0
a2+b2+c3=0

if there has infinitely solution then...
a1/a2=b1/b2=c1/c2

take... a1/a2=b1/b2

2/6=3/k
k =9

I hope it will help you ...so like it