Question

Find the value of 'k' such that 2/3,k,5/8 are three consecutive terms of an AP.

Answer 1

Answer:

Difference between the consecutive terms of AP can't be changed, which is also known as Common Difference.

Therefore :

Difference between 5 / 8 and k is equal to the difference between k and 2 / 3

5 / 8 - k = k - 2 / 3

5 / 8 + 2 / 3 = k + k

{ 3( 5 ) + 8( 2 ) } / 24 = 2k

{ 15 + 16 } 24 = 2k

31 / 24 = 2k

31 / ( 24 × 2 ) = k

31 / 48 = k

Therefore the value of k satisfying the given AP is 31 / 48