Question

find the value of k such that one of zero polynomial 3 X square + 1 + 4 K X + K square +5 is one third of other
of other​

Answer 1

Answer:

Step-by-step explanation:

Let a and a/3 are the roots of 3x^2+(1+4k).x+(k^2+5)=0.

a+a/3=-(1+4k)/3.

4a/3= -(1+4k)/3.

4a = -(1+4k).

a =-(1+4k)/4…………….(1)

a×a/3 =(k^2+5)/3.

a^2 = (k^2+5).

put a =-(1+4k)/4 from eq .(1).

{+(1+4k)^2}/16=(k^2+5).

1+16k^2+8k = 16k^2+80.

8k=79 => k = 79/8 .Answer.

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