Question

Find the value of K such that quadratic equation x²-2Kx+(7K-12)=0 has equal roots.

Answer 1

Answer:

Here's your answer

#If the polynomial have real and equal roots than...

D=0

b^2-4ac=0

4k^2 -4(7k-12) =0

Step-by-step explanation:

$4 {k}^{2} - 28k + 48 = 0 \\ \\ 4( {k}^{2} - 7 + 12) = 0 \\ \\ {k}^{2} - 7k + 12 = 0 \\ \\ {k}^{2} - 3k - 4k + 12 = 0 \\ \\ k(k - 3) - 4(k - 3) = 0$

$(k - 3)(k - 4) \\ \\ k = 3 \: \: and \: 4$

Hope it helps ✌