Question

Find the value of k such that sum of the squares of roots

Answer 1

Step-by-step explanation:

it is a quadratic equation.. so SUM of the roots is equal to -(first degree term coefficient/coefficient of second degree term )..and PRODUCT is (constant value/second degree term)

let a and b be the two roots

a+b=8,,ab=k,,, given a2+b2=40

now a2+b2=(a+b)2-2ab

40 =8*8-2*k

2*k=64-40=24

k=12!!

solved

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Answer 2

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Now, sum of the squares of the roots = 40.

⇒α^2+β^2=40

⇒α^2+β^2+2αβ−2αβ=40

⇒(α+β)^2−2αβ=40

⇒8^2−2×k=40

⇒64−2k=40

⇒−2k=40−64

⇒−2k=−24

⇒k=12