Question

Find the value of k such that system of linear equation 2x+4y+7=0 and 3x-ky+1=0 has no solution.

Answer 1

given:

2x+4y+7=0 ———————(1)

3x-ky+1=0—————————(2)


here,

a1=2, b1= 4 and c1=7, and

a2= 3, b2= -k and c2= 1

we know that,

for having parallel line( no solution),

a1/a2=b1/b2 ≠c1/c2

2/3=4/-k ≠ 7


2/3=4/-k

-2k= 4 x 3

k= -6