Find the value of k such that the equation 4z2-2(k+1)z+(k+4)=0 has equal roots
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Answered by
5
★ QUADRATIC RESOLUTION ★
GIVEN EQUATION :
☣ 4z² - 2( k + 1 ) z + ( k + 4 ) = 0
FOR EQUAL ROOTS :
☣ D = 0
☣ 4 ( k + 1 )² - 4 ( 4 ) ( k + 4 ) = 0
☣ k² + 1 + 2k - 4k - 16 = 0
☣ (k - 1)² = 16
☣ k - 1 = ± 4
☣ k = 5 , -3
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GIVEN EQUATION :
☣ 4z² - 2( k + 1 ) z + ( k + 4 ) = 0
FOR EQUAL ROOTS :
☣ D = 0
☣ 4 ( k + 1 )² - 4 ( 4 ) ( k + 4 ) = 0
☣ k² + 1 + 2k - 4k - 16 = 0
☣ (k - 1)² = 16
☣ k - 1 = ± 4
☣ k = 5 , -3
★✩★✩★✩★✩★✩★✩★✩★✩★✩★✩★
Answered by
4
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