Math, asked by gagan719260, 9 months ago

find the value of k such that the following equations have no solution.
1- kx- 8y = K+2
2- 6x- 3ky = 9

REMEMBER THAT IT IS FROM THE CHAPTER OF ( LINEAR EQUATION IN TWO VARIABLE ) ...

PLZ ANS IT STEP BY STEP....​

Answers

Answered by allekeerthi13
2

given pair of equations have no solutions

kx - 8y = k + 2

6x - 3ky = 9

a1 = k. b1 = -8. c1 = -k-2

a2 = 6. b2 = -3k. c2 = -9

a1/a2 = b1/b2

k/6 = -8/-3k

k × -3k = -8 × 6

-3k^2 = -48

k^2 = -48/-3

k =√16

k = 4

I think this is the answer..........I hope it helps you

Answered by harinni92
1

Step-by-step explanation:

If a pair of linear  equations is given by

a1x  +  b1y  +  c1 = 0

a2x  +  b2y  +  c2 = 0

When the system of linear equations will represent two Parallel Lines there is no point of intersection and consequently there is no pair of values of x and y which satisfy both equation. Thus, system has no solution and such pair of linear equation is inconsistent pair of  linear equations

For parallel lines (inconsistent) :

 a1 /a2 = b1/b2 ≠ c1/ c2

SOLUTION:

The Given pair of  linear equation is :

kx  - 8y  =  k + 2 …………(1)

6x  -  3ky  =  9……………..(2)

1a = k. b1 = -8. c1 = -k-2

a2 = 6. b2 = -3k. c2 = -9

a1/a2 = b1/b2

k/6 = -8/-3k

k × -3k = -8 × 6

-3k^2 = -48

k^2 = -48/-3

k =√16

k = 4

HOPE IT HELPS

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