find the value of k such that the following equations have no solution.
1- kx- 8y = K+2
2- 6x- 3ky = 9
REMEMBER THAT IT IS FROM THE CHAPTER OF ( LINEAR EQUATION IN TWO VARIABLE ) ...
PLZ ANS IT STEP BY STEP....
Answers
given pair of equations have no solutions
kx - 8y = k + 2
6x - 3ky = 9
a1 = k. b1 = -8. c1 = -k-2
a2 = 6. b2 = -3k. c2 = -9
a1/a2 = b1/b2
k/6 = -8/-3k
k × -3k = -8 × 6
-3k^2 = -48
k^2 = -48/-3
k =√16
k = 4
I think this is the answer..........I hope it helps you
Step-by-step explanation:
If a pair of linear equations is given by
a1x + b1y + c1 = 0
a2x + b2y + c2 = 0
When the system of linear equations will represent two Parallel Lines there is no point of intersection and consequently there is no pair of values of x and y which satisfy both equation. Thus, system has no solution and such pair of linear equation is inconsistent pair of linear equations
For parallel lines (inconsistent) :
a1 /a2 = b1/b2 ≠ c1/ c2
SOLUTION:
The Given pair of linear equation is :
kx - 8y = k + 2 …………(1)
6x - 3ky = 9……………..(2)
1a = k. b1 = -8. c1 = -k-2
a2 = 6. b2 = -3k. c2 = -9
a1/a2 = b1/b2
k/6 = -8/-3k
k × -3k = -8 × 6
-3k^2 = -48
k^2 = -48/-3
k =√16
k = 4
HOPE IT HELPS