Question

Find the value of k such that the polynomial () = 2 − ( + 6) + 2(2 − 1) has the sum of its zeros
equal to half of their product

Answer 1

Answer:

Step-by-step explanation:

Let the roots be α,β

For a quadratic equation ax2+bx+c=0

Sum of roots α+β=k+6⋯(1)

Product of roots αβ=4k−2⋯(2)

According to question,

α+β=2αβ​  

From (1),(2)

⟹k+6=2k−1

⟹k=7