Question

Find the value of k such that the polynomial x²-(k+6) X+2(2k-1) has sum of its zeroes equal to half of their product​

Answer 1

Answer:

Sum of zero = (-b)/a

= -(-(k+6)

=k+6

Product of zero

=c/a

= 2(2k-1) =4k-2

It is given in question

Sum of zero = 1/2 of product

K+6 = 1/2(4k-2

k+6 = 2k -1

6+1 = 2k-k

7 = k

Therefore k = 7

Answer 2

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