Find the value of k such that the polynomial x²-(k+6) X+2(2k-1) has sum of its zeroes equal to half of their product
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Answer:
Sum of zero = (-b)/a
= -(-(k+6)
=k+6
Product of zero
=c/a
= 2(2k-1) =4k-2
It is given in question
Sum of zero = 1/2 of product
K+6 = 1/2(4k-2
k+6 = 2k -1
6+1 = 2k-k
7 = k
Therefore k = 7
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