Find the value of k such that the polynomial x2 – (k+6) x + 2 (2k − 1) has sum of its
zeroes equal to half of the product of its zeroes.
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Answer:
Let the roots be α,β
For a quadratic equation ax
2
+bx+c=0
Sum of roots α+β=k+6⋯(1)
Product of roots αβ=4k−2⋯(2)
According to question,
α+β=
2
αβ
From (1),(2)
⟹k+6=2k−1
⟹k=7
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