Math, asked by anchal12388, 10 months ago

Find the value of k such that the quadratic equation has real and

equal roots.

i) x (x-2k) + 6 = 0 ii) 4x2 – 2 (k+1) x + k +1 = 0 ​

Answers

Answered by diba28993
0

Answer:

I. 2k=0

k=0

I.

ii. k+1=0

k=-1

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