Question

Find the value of k such that the quadratic equation x (x-2k) +6 =0 has real and equal roots​

Answer 1

Answer:

Step-by-step explanation:

Heya Friend!!

Here's ur ans with solution :-

☣ As we know if the quadratic equation has real and equal roots then it's discriminant should be equal to zero.

that is :- D = 0

x( x - 2k ) + 6 = 0

x² - 2kx + 6 = 0

From the equation,

a = 1

b = -2k

c = 6

And,

D = b²- 4ac

0 = (-2k)² - 4 × 1 × 6

0 = 4k² -24

24 = 4k²

24/4 = k²

6 = k²

±√6 = k

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Answer 2

Step-by-step explanation:

hope this answer will be helpful