Find the value of k such that the quadratic equation x2-2kx+(7k-12)=0 has equal roots
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pls mark as brainliest friend
Step-by-step explanation:
A = 1 , b = -2k , c = 7k-12
d = b^2 - 4ac
= 4k^2 - 4 × 1 × 7k-12
= 4k^2 - 28k + 48 = 0
= k^2 - 7k + 12 = 0
= (k-4) (k-3) = 0
= k = 4 , k = 3.
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