Question

Find the value of 'k' such that the quadratic polynomial:- x^2 - (k+6)x + 2(2k+1) has sum of zeroes is half of their product.​

Answer 1

Step-by-step explanation:

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Answer 2

Answer:

K=5

Step-by-step explanation:

Given:- X^2-(k+6)x+2(2k+1)

To find:- Value over k

Solution:-

Let us assume that this quadratic equation contains alpha and beta as two zeros...

Alpha+Beta=-b/a

Alpha+Beta=k+6

It is given that sum of roots are half of product of roots

Therefore,

Alpha×Beta=2(k+6)

Alpha×Beta=2k+12 (equation 1)

But we know that,

Alpha×Beta=c/a

Alpha×Beta=4k+2 (equation 2)

By this,

We can equate equation 1 and equation 2

4k+2=2(k+6)

4k+2=2k+12

2k= 10

K=10/2

K=5

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