Question

Find the value of k Such that the quadratic polynomial x²-(k+6)x+2(2k+1) has some of the zeros Is half of their product

Answer 1

Answer = 2/7

Step-by-step explanation:

product of zeroes = 1/2 x sum of zeroes

c/a = 1/2 x -(b/a)

(2(2k + 1))/1 = (k+6)/2

4k+2 = (k+6)/2

8k+4 = k+6

7k = 2

k = 2/7