Question

Find the value of k such that the the equation 9x2 + 8kx + 16 = 0 has realroots.​

Answer 1

Answer:

k=3 or k=-3 is the answer

Step-by-step explanation:

Given equation 9x²+8kx+16=0 has real and equal roots then discriminant is  zero

Discriminant=0

b²-4ac=0

(8k)²-4(9)(16)=0

64k²=64(9)

k²=9

k=3 or k=-3.