find the value of k such that x=2 and y=1 is a solution of the linear equation 2x-ky+7=8
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Answered by
29
2x-ky+7=8
2(2)-k(1)+7=8
4-k+7=8
11-k=8
k=3
2(2)-k(1)+7=8
4-k+7=8
11-k=8
k=3
Answered by
67
The given linear equation is:2x-ky+7=8
put x=2 and y=1,then
2(2)-k(1)+7=8
4-k+7=8
4-k=8-7
4-k=1
or,k=4-1
k=3
Hope this is the answer that u are looking for,if it is the answer that u are looking for then plzzzz mark it as the brainliest answer
put x=2 and y=1,then
2(2)-k(1)+7=8
4-k+7=8
4-k=8-7
4-k=1
or,k=4-1
k=3
Hope this is the answer that u are looking for,if it is the answer that u are looking for then plzzzz mark it as the brainliest answer
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