Question

find the value of k such that x=2 and y=1 is a solution of the linear equation 2x-ky+7=8

Answer 1

2x-ky+7=8
2(2)-k(1)+7=8
4-k+7=8
11-k=8
k=3

Answer 2

The given linear equation is:2x-ky+7=8
put x=2 and y=1,then
2(2)-k(1)+7=8
4-k+7=8
4-k=8-7
4-k=1
or,k=4-1
k=3

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