find the value of k such that (x-2) is a factor of the polynomial x^3+kx^2-5x-6
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p(x)= x^3+kx^2-5x-6
g(x)= (x-2)
zero of g(x):-
x-2=0
x=0+2
x=2
putting 2 in p(x)
p(2)=(2)^3+k(2)^2-5(2)-6
8+4k-10-6 = 0 (as it is a fcator)
-8+4k=0
4k=8
so k=2
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Answered by
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Step-by-step explanation:
if the give (x-2) is a factor than the equation bes'
x³ + kx² - 5x - 6=0
and the equation solves as follows........
thanks you
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