Question

Find the value of k such that

(x²-2x + k) leaves a remainder 3 when divided by ( x + 1 ) ​

Answer 1

Answer:

given equation satisfies when x is equal to -1 remainder =3

Step-by-step explanation:

${x}^{2} - 2x + k = 3 \\ x = - 1 \\ by \: substuting \: x \: value \: we \: get \\ ( { - 1})^{2} - 2( - 1) + k = 3 \\ 1 + 2 + k = 3 \\ 3 + k =3 \\ k = 3 - 3 \\ k = 0$