Question

find the value of K
$(7) {}^{ - 3} \times (7) {}^{3k + 2} = (7) {}^{ 15} \div (7) {}^{8}$
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Answer 1

Answer:

$k \: = \frac{8}{3}$

Step-by-step explanation:

${7}^{ - 3} . {7}^{3k + 2} = {7}^{15} \div {7}^{8}$

${7}^{ - 3 + 3k + 2} = {7}^{15 - 8}$

${7}^{3k - 1} = {7}^{7}$

$3k - 1 = 7$

$3k = 8$

$k = \frac{8}{3}$