Question

find the value of K
$\frac{1}{2} \times 8 - 2k$
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Answer 1

Solution :

$\frac{1}{2} \times 8 - 2k = 0$

$4 - 2k = 0$

$2(2 - k) = 0$

$2 - k = 0$

$- k = - 2$

$k = 2$

Verification :

$\frac{1}{2} \times 8 - 2(2) = 0$

$4 - 4 = 0$

$0 = 0$

Hence , L.H.S = R.H.S