Math, asked by abi5748, 1 year ago

find the value of k
 {x}^{2} - 2kx + {7k - 12} = 0

Answers

Answered by Anonymous
4
What is the value of x???

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Answered by honeysingh96
2
For equal roots
b sq =4 ac
(-2k)sq = 4 .1.(7k -12)
4 k sq = 4(7k-12)
k sq = 7k -12
k sq - 7k +12=0
k sq -4k -3k +12=0
k (k -4)-3(k-4)=0
(k-4)(k-3)=0
ie k=3,4 ans

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