find the value of k the following pair of equation has no solution x+2y=3,(k-1)x+(k+1)y=k+2
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Answered by
40
Hey
Here is your answer,
The given equations is
x + 2y = 3
(k-1)x + (k+1)y = k+2
As, we know that, for the given system to have no solution,
1/k-1 = 2/k+1
K+1=2k-2
-k=-3
K=3
Hope it helps you!
Here is your answer,
The given equations is
x + 2y = 3
(k-1)x + (k+1)y = k+2
As, we know that, for the given system to have no solution,
1/k-1 = 2/k+1
K+1=2k-2
-k=-3
K=3
Hope it helps you!
Answered by
12
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