Question

find the value of k the pair of linear equations 3x+2y-5=0 and kx-y+3=0 has unique solution​

Answer 1

Answer:

The Given pair of linear equation is :

3x +2y = -5

3x +2y +5= 0………(1)

x -ky=2

x -ky -2 = 0…………(2)

On comparing with General form of a pair of linear equations in two variables x & y is: a1x + b1y + c1 = 0

and a2x+b2y + c2= 0

a1= 3, b1= 2, c= 5

a2= 1 , b2= -k , c= -2

a1/a2= 3/1 , b1/b2= 2/-k & c1/c2= 5/-2

Given: A pair of linear equations has a Unique solution if

a1/a2 ≠ b1/b2

3/1 ≠ 2/-k

3× -k ≠ 2

k ≠ -⅔

Hence, the value of k ≠ -⅔.

Answer 2

Answer:

k= -3/2

Step-by-step explanation:

a1/a2=b1/b2=c1/c2

3/k=2/-1

2k= -3

k= -3/2