find the value of k the quadric equation where root are given x2+kx+4=0
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Answer:
x^2+kx+4=0
b^2-4ac=0
k^2-4*1*4=0
k^2-16=0
k^2=16
k=√16
k=± 4
Hence, the value of k is ± 4 .
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