Math, asked by musheer128, 1 year ago

find the value of k the root of the equation x^2+4x+k=0 are real​

Answers

Answered by QuickSilver04
2

\large{\implies{Answer}}

for real roots the condition is

 b {}^{2}  - 4ac = 0

(4) {}^{2}  - 4(1)(k) = 0 \\ 16 - 4k = 0 \\  - 4k =  - 16 \\ k =  \frac{ - 16}{ - 4}

\large{\implies{\blue{k=4}}}

Similar questions