Question

Find the value of k the roots of the quadratic equation is 2 x square - 6 X + 3 is equals to zero are real and equal

Answer 1

where is the K in the question......???

Answer 2

If the roots of a quadratic equation are real and equal then

Discriminant(b^2 - 4ac) of  Quadratic equation is zero.

It is given a quadratic equation

2x2- 6x + k = 0,

the roots of  are real and equal.

Therefore Discriminant of  Quadratic equation is zero.

b^2 - 4ac =0

The coefficients of  2x2- 6x + k = 0,

a = 2

b = -6

c = k

To find the value of k

b^2 - 4ac =0

(-6)^2 - 4 x 2x k = 0

8k = 36

k = 36/8 = 9 /2 = 4.5