find the value of k to get equal roots
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If the equation 2kx 2-4+1=0 has equal toroots then the value of k is=0
ruquua:
i want the ans for 2x2+kx+3
that is 2 yax square not 2x2
ok
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2x² + kx + 3= 0
a = 2, b = k , c = 3
Comparing equation with ax²+ bx + c = 0, we obtain
a = 2, b = k, c = 3...
Discriminant = b²− 4ac = (k)²− 4(2) (3) .
= k² − 24.
For equal roots,
Discriminant = 0
k²− 24 = 0
k²= 24
K=√24
K=+2√6 or -2√6
a = 2, b = k , c = 3
Comparing equation with ax²+ bx + c = 0, we obtain
a = 2, b = k, c = 3...
Discriminant = b²− 4ac = (k)²− 4(2) (3) .
= k² − 24.
For equal roots,
Discriminant = 0
k²− 24 = 0
k²= 24
K=√24
K=+2√6 or -2√6
gussed kya
ik dont no
12 x2
root 24
oh
how
√24 is in points
√24 ka ans points me atta
i dont no this problem my sister me
ok bye gnight
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