Question

find the value of k to so that Quadratic equation has equal roots
1. kx ( x-1 ) - 5 = 0
2. 4x^2 - x + k = 0

pls answer with solution​

Answer 1

Answer:

For first question:k=0 and k=20

For second question:k=1/16

Step-by-step explanation:

As we know that in a quadratic equation , for equal roots we put D=b^2-4ac=0.

IN FIRST QUESTION

First we resolve the equation:

kx(x-1)-5=0 as kx^2-kx-5=0;

Here, b=(-k),a=k,c=5,

now put D=b^2-4ac=0;

k^2-20k=0;

k=0,k=20.

here is your answer.

FOR SECOND QUESTION;

We do as we have done in first question,

here,b=(-1),a=4,c=k;

now do D=0;

1-4*4*k=0;

1-16k=0;

k=1/16.

here is your second answer.

hope you understand it very well, THANKS...