find the value of k when factor is x-1=0. p(x)=12x^2-3x+k
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1
Answer:
p(x) = 12x²-3x+k
zero of the given factor is 1
so, p(1)=12(1)²-3(1)+k
= 12-3+k
= 9+k
9+k=0
k= - 9
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here I solved your question✌✌
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Answer:
To find f(k) , determine the remainder of the polynomial f(x) when it is divided by x−k . k is a zero of f(x) if and only if (x−k) is a factor of f(x) . Each rational zero of a polynomial function with integer coefficients will be equal to a factor of the constant term divided by a factor of the leading coefficient
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