Math, asked by Ranjandeka, 10 months ago

Find the value of K, when
(K+1)x + 5y +25 = 0
3x+(k-1) y+15 = 0
Are for infinite solutions

Answers

Answered by PonnalaChiranjeevi

2

Answer:

a1/a2=b1/b2=c1/C2

k+1/3=5/k-1=25/15

k+1/3=5/k-1

(k+1)(k-1)=15

k2-1=15

K2=16

k=√16

k=4

Step-by-step explanation:

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