Question

Find the value of k when kx^2+2x+1=0 has real and distinct roots in "video"

Answer 1

Solution:

The given quadratic equation is, k x²+2 x +1=0

For,a quadratic equation of type, ax²+b x +c=0, Roots will be real and distinct only when,

D=Discriminant= b²-4 a c

D≥0

2^2-4 k ≥ 0

4 - 4 k≥0

4≥4 k

Dividing both sides by 4, we get

k≤1

That is, k∈ [-∞,1]