find the value of k when the distance between the points (3 ,2K) and (4,1) is √10 units
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Answered by
258
Hello users...
Solution:-
We know that:
Distance between two points
A(a,b) and B(c,d)
=> AB = √(c-a)² +(d-b)²
Here,
According to question.
√10 = √(4-3)² + ( 1-2k)²
=> 10 = 1 + (1-2k)²
=> 9 = (1-2k)²
=> ±3 = (1-2k)
=> 1-2k = 3 and 1-2k= -3
=> -2k = 2 and -2k = -4
=> k = -1 and k = 2
=> k = -1,2 Answer
✡⭐ Hope it helps ✡⭐
Solution:-
We know that:
Distance between two points
A(a,b) and B(c,d)
=> AB = √(c-a)² +(d-b)²
Here,
According to question.
√10 = √(4-3)² + ( 1-2k)²
=> 10 = 1 + (1-2k)²
=> 9 = (1-2k)²
=> ±3 = (1-2k)
=> 1-2k = 3 and 1-2k= -3
=> -2k = 2 and -2k = -4
=> k = -1 and k = 2
=> k = -1,2 Answer
✡⭐ Hope it helps ✡⭐
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Answered by
40
Ans: this question is to be solved by distance formula..
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