Find the value of k when the distance between the points (3'2k) and (4'1) us root 10units
Answers
Answered by
3
The points are (3,2k) and (4,1)
(Distance)²=(x₂-x₁)²+(y₂-y₁)²
10=(4-3)²+(1-2k)²
10=1+1+4k²-4k
4k²-4k-8=0
k²-k-2=0
(k-2)(k+1)=0
Hence the values of k are 2 and -1
(Distance)²=(x₂-x₁)²+(y₂-y₁)²
10=(4-3)²+(1-2k)²
10=1+1+4k²-4k
4k²-4k-8=0
k²-k-2=0
(k-2)(k+1)=0
Hence the values of k are 2 and -1
Similar questions