find the value of K? when the vertices of the triangle are the points are (2,9),(-2,1) ,(k,3). and the are is 28 square unit?
Answers
Answered by
0
Answer:
hope it helps you a LITTLE Bit:-))
Attachments:
Answered by
2
Step-by-step explanation:
[-2 ,9 ,1]
[ 2 ,1 , 1] = 28
[ k, 3 , 1 ]
28 = 1 /2 [ 2 ( 1 - 3 ) - 9 [ - 2 - k ] + 1 ( -6 - 1 ) ]
56 = -4 + 18 + 9k - 6- k
56 = 8 + 8k
56 - 8 / 8 = k
48 / 8 = k
k = 6
please make me brainlest
Similar questions