find the value of K where 31K2 is Divisible by 6
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Answered by
16
Answer:
K should be a number that would make the whole number divisible by 3
Therefore K = 0,3,6,9
Answered by
27
Step-by-step explanation:
we take K as - 0,3,6,9.
bcs a number is divisible by 6 when it is multiple of 2&3.
it is divisible by 2 because it's unit digit is 2
and if it is divisible by 3 their sum is also divisible by 3
that means- 3+1+K+2= multiple of 3
1. 3+1+0+2=6
2. 3+1+3+2=9
3. 3+1+6+2=12
4. 3+1+9+2=15
HOPE THIS HELPS YOU
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