Question

find the value of k where 31k2 is divisible by 6​

Answer 1

...............,.......

Answer 2

Answer:

Least value of K = 0

Step-by-step explanation:

We can write 6 as 3 *2

So the number must be divisible by both 3 and 2

The number 31k2 is even

Therefore divisible by 2

To get divided by 3

The sum of digits of a number should be divisible by 3

Therefore

3 + 1 + k + 2

= 6 + k

Here least value of K is 0 bcz 6 is divisible by 3

Value of K = 0, 3, 6, 9....

For example

6 + 0 = 6 3102 / 6 = 517

6+ 3 = 9 3132 / 6 = 522

HOPE IT'S HELPFUL