find the value of k where31k2 is divisible by 6
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31k ÷6=1
=> 31k2=1÷6
=>k2=31÷6
=> k= 31÷12
=>k=2.416 approximately.
=> 31k2=1÷6
=>k2=31÷6
=> k= 31÷12
=>k=2.416 approximately.
aaru34:
not satisfied
I don't know what would then
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