find
the value of K which each of the following system
of equations has a unique
4x-5y=k,2x-3y=12
Answers
Answered by
0
Answer:
k = y+24.
Step-by-step explanation:
4x-5y=k ....eq1
2x-3y=12 ....eq2
eq2....multiply by 2. it becomes 4x-6y=24
eq1 minus eq2.
y = k-24.
so, k = y+24.
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