Question

Find the value of k which equation has two roots 2x^+kx+3=0

Answer 1

The given equation is 2x2 + kx + 3 = 0
Here, a = 2  ;  b = k  ; c = 3
For equal roots, D = 0
 So,  b2 - 4ac = 0
 ⇒ k2 - 24 = 0
 ⇒ k = ± 2√6


HOPE it helps you

Answer 2

Heya mate, Here is ur answer

We know that any equation to have two equal roots , the discriminant D should be equal to 0.

D= b^2-4ac

Here

b=K

a= 2

c=3

So, D= k^2-4×2×3

D=0 (as the roots are equal)

0=k^2-24

24= k^2

2√6=k

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