find the value of k which equvation 2x^+16=0 has real and equal roors
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where is k in this equation
if k is in with 16, then answer will be
2x²+16k=0
by the formula of discriminant
D=b²-4ac. (a=2,b=16k and c=0)
put value of a,b and c in the formula of D
(16k)²-4(2)(0)
16k²-8(0)=0
16k²=0
K²=16
k=√16
k=4
so, the value of k is 4
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if k is in with 16, then answer will be
2x²+16k=0
by the formula of discriminant
D=b²-4ac. (a=2,b=16k and c=0)
put value of a,b and c in the formula of D
(16k)²-4(2)(0)
16k²-8(0)=0
16k²=0
K²=16
k=√16
k=4
so, the value of k is 4
HOPE IT IS HELPFUL!
PLZ MARK IT AS BRAINLIEST!
sumayyamuhammed:
thx
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in your question k is not present
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