Question

find the value of k which polynomial x 4 x root 4 minus 4 x root 2 + 2 X + K 2 S 80

Answer 1

$p(l) = x4 {x}^{4} - 4 {x}^{2} + 2x + k {2}^{2} 80 = 0 \\ = > 4 {x}^{5} - 4 {x}^{2} + 2x + k320 = 0 \\ = > 4 {x}^{5} - 4 {x}^{2} + 2x = - k320 \\ = > - k = \frac{4 {x}^{5} - 4 {x }^{2} + 2x }{320} \\ = > k = - 1( \frac{4 {x}^{5} - 4 {x}^{2} + 2x}{320} ) \\ = > k = \frac{ - 4 {x}^{5} + 4 {x}^{2} + 2x }{ - 320}$
hope it will help you. Plz mark this as a brianliest answer. THANK YOU....

Answer 2

hope it will help you. Plz mark this as a brianliest answer.