Question

find the value of k which the following terms are in A.P.
2k+1,k sq.+k+1,3k sq.-3k+3​

Answer 1

Step-by-step explanation:

I don't know ANSWER

your an other question I think

I can help you

Answer 2

Answer: k = 1,2

Step-by-step explanation:

2k+1 , k^2+k+1 , 3k^2-3k+3

For this to be an AP....

3k^2 - 3k + 3 - k^2 - k - 1 = k^2 + k + 1 - 2k - 1

Simplifying,

k^2 - 3k + 2 = 0

(k-1)(k-2) = 0

k = 1 , 2

I hope u got ur answer...