Question

find the value of k, (x-1) is the factor of x^2+9x-5+k​

Answer 1

Answer:

k=-5

Step-by-step explanation:

if (x-1) is factor of x²+9x-5+k

to find value of K

\begin{gathered} {x}^{2} + 9x - 5 + k = 0 \\ \\ {1}^{2} + 9 \times 1 - 5 + k = 0 \\ \\ 1 + 9 - 5 + k = 0 \\ \\ 5 + k = 0 \\ \\ k = - 5\end{gathered}

x

2

+9x−5+k=0

1

2

+9×1−5+k=0

1+9−5+k=0

5+k=0

k=−5

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Answer 2

Answer:

-5

Step-by-step explanation:

(x-1)=0

x=1

If (x-1) is the factor of x^2+9x-5+k

Therefore, p(1)= 0

1²+9(1) -5+k=0

1+9-5+k=0

k= -5

HOPE YOU UNDERSTOOD THE SOLUTION