Find the value of k, (x-1)is the factor of x2+9x
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Answered by
0
Answer:
Answer:
k=-5
Step-by-step explanation:
Given----->
if (x-1) is factor of x²+9x-5+k
to find value of K
\begin{gathered} {x}^{2} + 9x - 5 + k = 0 \\ \\ {1}^{2} + 9 \times 1 - 5 + k = 0 \\ \\ 1 + 9 - 5 + k = 0 \\ \\ 5 + k = 0 \\ \\ k = - 5\end{gathered}x2+9x−5+k=012+9×1−5+k=01+9−5+k=05+k=0k=−5
Answered by
0
Answer:
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Step-by-step explanation:
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